if A B C D and E are points in a plane such that the line CD bisects angle ACb and line CB bisects right angle ACE ,then DCE=?
Created: 5 years ago |
Updated: 6 months ago
best des
Angle ACE = 90 degree since CB bisects ACE then BCE = 45 degree
ACB = 45 degree.
Since CD bisects ACB We get two angles ACD = 45/2 = 22.5 and DCB = 45/2 = 22.5
DCE = DCB + BCE = 22.5 + 45 = 67.5
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